3(x^2+120x-17800)=0

Solution for 3(x^2+120x-17800)=0 equation:

3(x^2+120x-17800)=0

We multiply parentheses

3x^2+360x-53400=0

a = 3; b = 360; c = -53400;
Δ = b2-4ac
Δ = 3602-4·3·(-53400)
Δ = 770400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{770400}=\sqrt{3600*214}=\sqrt{3600}*\sqrt{214}=60\sqrt{214}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(360)-60\sqrt{214}}{2*3}=\frac{-360-60\sqrt{214}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(360)+60\sqrt{214}}{2*3}=\frac{-360+60\sqrt{214}}{6}
$